electric force and fields answers holt physics
(3 \times 10^{-6})(2 \times 10^{-6})}{(0.5)^2} \] Step 3: Calculate: \[ F \approx 8.988 \times 10^9 \times \frac{6 \times 10^{-12}}{0.25} \] \[ F \approx 8.988 \times 10^9 \times 24 \times 10^{-12} \] \[ F \approx 215.7 \times 10^{-3} \, \text{